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Q. $ \lim_ {{x \to 0}} \frac {log\, cosx} {x} $ Is equal to

Solution:

$ \lim_ {{x \to 0}} \frac {log\, cos \, x} {x} $ = $ \lim_ {{x \to 0}} \frac{\frac{1}{cos \, x } . sin \, x}{1}$ = = 0(By L Hospital's Rule)