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Q. $ \lim_{x \to {0}} \frac {a^x-b^x} { x } $is

Solution:

$\lim_{x\to0} \frac{a^{x} - b^{x}}{x} =\lim_{x\to0} \frac{\left(a^{x} -1 \right) -\left(b^{x} -1\right)}{x} $
= $\lim_{x\to0} \frac{a^{x} -1}{x} - \lim _{x\to 0} \frac{b^{x } -1}{x}$
= $\log \, a - \log\, b = \log\left(\frac{a}{b}\right)$