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  4. Light of wavelength 5000 Å is incident over a slit of width 1 μm . The angular width of central maxima will be

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Q. Light of wavelength $5000 \, Å$ is incident over a slit of width $1 \, μm$ . The angular width of central maxima will be

NTA AbhyasNTA Abhyas 2020Wave Optics

Solution:

For first minima
$sin\theta =\frac{\lambda }{a}=\frac{5000 \times 10^{- 10}}{1 \times 10^{- 6}}=\frac{1}{2}$
$\Rightarrow $ $\theta =30^\circ $
So the angular width of the central maxima is
$2\theta =60^\circ $