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Q. Light of wavelength $500 \,nm$ is used to form interference pattern in Young's double slit experiment. A uniform glass plate of refractive index $1.5$ and thickness $0.1 \,mm$ is introduced in the path of one of the interfering beams. The number of fringes which will shift the cross wire due to this is

Wave Optics

Solution:

The number of fringes shifting is decided by the extra path difference produced by introducing the glass plate. The extra path difference is $(\mu-1) t=n \lambda$ or $(1.5-1) \times 0.1 \times 10^{-3}=n \times 500 \times 10^{-9}$
$=n=100$