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Q. $LiCl$ has $NaCl$ type structure with edge length $512$ pm. Assuming that the $Li^{+}$ ion is small enough that the chloride ions are in contact, then radius of $Cl^{-}$ ion is
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The Solid State

Solution:

$\sqrt{2 a}=4 r_{C l}^{-}$
$4 r_{C l^{-}}=\frac{a \sqrt{2}}{4}=\frac{a}{2 \sqrt{2}}=\frac{512}{2 \sqrt{2}}$
$=361.8 pm \cong 362 pm$