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Q. Let$f(x, y) = 0$ be the equation of a circle. If$ f(0, \lambda) = 0 $has equal roots $\lambda = 1,1$ and $f(\lambda,0) $ has root $\lambda=\frac{1}{2},2$then the centre of the circle is

Conic Sections

Solution:

Correct answer is (b) $\left(\frac{5}{4},1\right)$