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Q. Let $ y=x $ be a function defined by $ \therefore $ The $ \frac{{{x}_{1}}+4}{2}=\frac{{{y}_{1}}-3}{2} $ is

JamiaJamia 2014

Solution:

Given, $ {{(Kg)}^{1/2}} $ such that $ {{(Kg)}^{-1/2}} $ It is clear that for every negative value of x, $ {{(Kg)}^{2}} $ . So, it is many-one. for $ {{(Kg)}^{-2}} $ , $ \frac{pV}{nT} $ $ \frac{pV}{nT}\frac{pV}{nT}\upsilon ersus $ $ {{T}_{1}}>{{T}_{2}} $ Range of $ \frac{pV}{nT} $ . Thus, $ 4\times {{10}^{3}}A{{m}^{-1}} $ is into. Hence, $ \text{1}{{0}^{-\text{2}}} $ is many-one onto.