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Q. Let $y=g(x)$ be the inverse of a bijective mapping $f: R \rightarrow R f(x)=3 x^3+2 x$. The area bounded by the graph of $g(x)$, the $x$-axis and the ordinate at $x=5$ is :

Application of Integrals

Solution:

image
note for inverse function $y$ axis will be the $x$ axis and $x$ axis will be the $y$ axis
$\text { required area } =\text { Area of rectangle }-\int\limits_0^1 f(x) d x $
$ =5-\int\limits_0^1\left(3 x^3+2 x\right) d x $
$=5-\left(\frac{3}{4}+1\right)=3 \frac{1}{4}=\frac{13}{4} $