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Q. Let $x$ be a random variable such that the probability function of a distribution is given by
$P(X=0)=\frac{1}{2}, P(X=j)=\frac{1}{3^{j}}(j=1,2,3, \ldots \ldots, \infty)$, Then the mean of the distribution and $P(X$ is positive and even) respectively are:

JEE MainJEE Main 2021Probability - Part 2

Solution:

mean $=\sum x_{1} p_{i}=\displaystyle\sum_{r=0}^{\infty} r \cdot \frac{1}{3^{r}}=\frac{3}{4}$
$p(x$ is even $)=\frac{1}{3^{2}}+\frac{1}{3^{4}}+\ldots . \infty$
$=\frac{\frac{1}{9}}{1-\frac{1}{9}}=\frac{1 / 9}{8 / 9}=\frac{1}{8}$