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Q. Let $x = 2$ be a root of $y = 4x^2 - 14x + q = 0$. Then $y$ is equal to

KEAMKEAM 2017Complex Numbers and Quadratic Equations

Solution:

We have
$y=4 x^{2}-14 x+q=0$
Since, $x=2$ is the root
$\therefore 4(2)^{2}-14(2)+q=0$
$\Rightarrow 16-28+q=0$
$\Rightarrow q=12$
$\therefore y=4 x^{2}-14 x+12$
$=4 x-8 x-6 x+12$
$=4 x(x-2)-6(x-2)$
$=(x-2)(4 x-6)$