1. Tardigrade
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  3. Mathematics
  4. Let X = -1, 0, 1 Y= 0, 2 and a function f: X → Y defined by y= 2x4, is

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Q. Let $X = \{-1$, $0$, $1\}$, $Y= \{0$, $2\}$ and a function $f : X \to Y$ defined by $y= 2x^4$, is

Relations and Functions - Part 2

Solution:

We have, $y = 2x^4$
$\therefore y (-1) = y( 1) = 2$, $y(0) = 0$ (many-one onto)
Here, we see that for two different values of $x$, we will get a same image and no element of $y$ is left, which do not have pre-image. So, function is many-one onto.