1. Tardigrade
  2. Question
  3. Mathematics
  4. Let X = 0, 1, 2, 3 and Y = -1, 0, 1, 4, 9 and a function f: X → Y defined by y = x2, is

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Q. Let $X = \{0$, $1$, $2$, $3\}$ and $Y = \{-1$, $0$, $1$, $4$, $9\}$ and a function $f$ : $X \to Y$ defined by $y = x^2$, is

Relations and Functions - Part 2

Solution:

$y(0) = 0$, $y( 1) = 1$, $y(2) = 4$, $y(3) = 9$. No two different values of $x$ (where $x \in x$) gives same image. Also $-1$ is element of set $Y$, which does not have its pre-image in set $X$. So, function is one-one into.