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Q. Let $U$ be a Universal set and $n(U)=12$. If $A, B \subseteq U$ are such that $n(B)=6$ and $n(A \cap B)=2$ then $n\left(A \cup B^{\prime}\right)$ is equal to

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Solution:

$n\left(A \cup B^{\prime}\right)=n(A)+n\left(B^{\prime}\right)-n\left(A \cap B^{\prime}\right) $
$=n(A)+n(U)-n(B)-(n(A)-n(A \cap B))$
$=n(U)-n(B)+n(A \cap B) $
$=12-6+2=8$