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Mathematics
Let Tn denote the number of triangles which can be formed by using the vertices of a regular polygon of n sides. If Tn+1 -Tn = 36, then n is equal to
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Q. Let $T_n$ denote the number of triangles which can be formed by using the vertices of a regular polygon of $n $ sides. If $T_{n+1} -T_n = 36$, then $n $ is equal to
KEAM
KEAM 2014
Permutations and Combinations
A
2
B
5
C
6
D
8
E
9
Solution:
Given, $T_{n+1}-T_{n}=36$
$\therefore { }^{n+1} C_{3}-{ }^{n} C_{3}=36$
$\Rightarrow \frac{(n+1) n(n-1)}{3 \cdot 2 \cdot 1}-\frac{n(n-1)(n-2)}{3 \cdot 2 \cdot 1}=36$
$\Rightarrow \frac{n(n-1)}{6}[n+1-n+2]=36 $
$\Rightarrow \frac{n(n-1) \cdot 3}{6}=36 $
$ \Rightarrow n(n-1)=72 $
$\Rightarrow n(n-1)=9 \times 8 $
$\therefore n=9$