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Q. Let the quadratic equation x2+3xk=0 has roots a,b and x2+3x10=0 has roots c,d such that modulus of difference of the roots of the first equation is equal to twice the modulus of the difference of the roots of the second equation. If the value of ' k ' can be expressed as rational number in the lowest form as m/n then find the value of (m+n).

Complex Numbers and Quadratic Equations

Solution:

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 given |ab|=2|cd|
(ab)2=4(cd)2
(a+b)24ab=4[(c+d)24cd]
9+4k=4[9+40]
4k=27+160=187k=1874
m+n=191