Thank you for reporting, we will resolve it shortly
Q.
Let the normal at the point $P$ on the parabola $y ^{2}=$ $6 x$ pass through the point $(5,-8)$. If the tangent at $P$ to the parabola intersects its directrix at the point $Q$, then the ordinate of the point $Q$ is :
Equation of normal : $y =- tx +2 at + at ^{3} \left( a =\frac{3}{2}\right)$
since passing through $(5,-8)$, we get $t =-2$
Co-ordinate of $Q:(6,-6)$
Equation of tangent at $Q : x +2 y +6=0$
Put $x=\frac{-3}{2}$ to get $R \left(\frac{-3}{2}, \frac{-9}{4}\right)$