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Q. Let $T _1$ be surface tension between solid and air, $T _2$ be the surface tension between solid and liquid and $T$ be the surface tension between liquid and air. Then in equilibrium, for a drop of liquid on a clean glass plate, the relation is.Physics Question Image

Mechanical Properties of Fluids

Solution:

$T_1+T \cos (\pi-\theta)=T_2$
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$\therefore \cos (\pi-\theta)=\frac{T_2-T_1}{T} $
$\therefore \cos \theta=\frac{T_1-T_2}{T}$