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Q. Let $T _{1}$ and $T _{2}$ be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr's model of an atom, the ratio $T _{1}: T _{2}$ is :

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Solution:

First excited state $\Rightarrow n =2$
$T _{1}=-13.6 \frac{ z ^{2}}{ n ^{2}}=-\frac{13.6}{4} eV$
Second excited state $\Rightarrow n =3$
$ T _{2}=-13.6 \frac{ z ^{2}}{ n ^{2}}=-\frac{13.6}{9} eV $
$ T _{1}: T _{2}=\frac{1}{4}: \frac{1}{9}=9: 4$