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Q. Let $S$ is a circle with centre $(0, \sqrt{2})$. Then
[A rational point is a point both of whose coordinates are rational numbers

Conic Sections

Solution:

The equation of the circle $S$ is $x ^{2}+( y -\sqrt{2})^{2}= r ^{2} \,\,\,\,\,\,....(1)$
Let the coordinates of any point on this circle be $( h , k )$, then
$h ^{2}+( k -\sqrt{2})^{2}= r ^{2} $
$\Rightarrow k =\sqrt{2} \pm \sqrt{ r ^{2}- h ^{2}} \,\,\,\,\,\,...(2)$
Since the above value of k contains a constant irrational number $\sqrt{2}$, therefore, the only possible rational value of $k$ is 0 .
Hence, $\sqrt{2} \pm \sqrt{r^{2}-h^{2}}=0$
$ \Rightarrow r^{2}-h^{2}=2 $
$\Rightarrow h=\pm \sqrt{r^{2}-2}$