1. Tardigrade
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  3. Mathematics
  4. Let R = x , y): x, y ∈ A, x + y = 5 where A = 1, 2, 3, 4, 5 then

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Q. Let $R = \{ \{x , y) : x, y \in A, x + y = 5\}$, where $A = \{1, 2, 3, 4, 5\}$, then

Relations and Functions - Part 2

Solution:

$R = \{(1, 4), (4, 1), (2, 3), (3, 2)\}$, $\therefore R$ is not reflexive as $(1, 1) \notin R$. Also, $R$ is symmetric by definition and not transitive as $(1, 4) \in R, (4, 1) \notin R$ but $(1, 1) \notin R$.