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  4. Let R be the region satisfying y< x2+1, y >x-1, x< 1 and x >0, then area of R is

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Q. Let $R$ be the region satisfying $y< x^2+1, y >x-1, x< 1$ and $x >0$, then area of $R$ is

Application of Integrals

Solution:

image
$A =\int\limits_0^1\left(\left( x ^2+1\right)-( x -1)\right) dx $
$=\int\limits_0^1\left( x ^2- x +2\right) dx $
$=\frac{11}{6}$