Tardigrade
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Tardigrade
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Mathematics
Let R be the real line. Let the relations S and T on R be defined by S= (x, y): y=x+1,0< x< 2 T= (x, y):(x-y) is an integer . Then
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Q. Let $R$ be the real line. Let the relations $S$ and $T$ on $R$ be defined by $S=\{(x, y): y=x+1,0< x< 2\}$, $T=\{(x, y):(x-y)$ is an integer $\} .$ Then
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WBJEE 2021
A
both $S$ and $T$ are equivalence relations on $R$
B
$T$ is an equivalence on $R$ but $S$ is not
C
neither $S$ nor $T$ is an equivalence relation on $R$
D
$S$ is an equivalence relation on $R$ but $T$ is not
Solution:
$T$ is an equivalence but $S$ is not