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Q. Let $ P(1, 2) $ and $ Q(-4, -8) $ be two points in a plane, Let $ A $ and $ B $ be two points on the line segment $ PQ $ such that $ PA = AB = BQ $ . Then the midpoint of $ AB $ is

J & K CETJ & K CET 2016Straight Lines

Solution:

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Since $PA = AB = BQ$
Then the mid point of $AB$ is also the mid point of $PQ$
$\therefore (x, y)\equiv (\frac{1-4}{2}, \frac{2-8}{2}) \equiv (\frac{-3}{2}, -3)$