1. Tardigrade
  2. Question
  3. Mathematics
  4. Let OA , OB , OC be coterminous edges of a cube. If l, m , n be the shortest distance between the sides OA , OB , OC and their respective skew body diagonals to them respectively then ((1/l2)+(1/ m 2)+(1/ n 2)):((1/ OA 2)+(1/ OB 2)+(1/ OC 2)) is equal to

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Q. Let $OA , OB , OC$ be coterminous edges of a cube. If $l, m , n$ be the shortest distance between the sides $OA , OB , OC$ and their respective skew body diagonals to them respectively then $\left(\frac{1}{l^2}+\frac{1}{ m ^2}+\frac{1}{ n ^2}\right):\left(\frac{1}{ OA ^2}+\frac{1}{ OB ^2}+\frac{1}{ OC ^2}\right)$ is equal to

Vector Algebra

Solution:

Correct answer is (a) 2