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Q. Let $n_{r}$ and $n_{b}$ be respectively the number of photons emitted by a red bulb and a blue bulb of equal power in a given time

NTA AbhyasNTA Abhyas 2020

Solution:

$P_{R e d}=P_{B l u e}$
$n_{r}\frac{h c}{\lambda _{r}}=n_{b}\frac{h c}{\lambda _{b}}$
$\frac{n_{r}}{n_{b}}=\frac{\lambda _{r}}{\lambda _{b}}$
As $\lambda _{r}>\lambda _{b}$
$\therefore $ $n_{r}>n_{b}$