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Q.
Let $h(x)=\min \left(x, x^{2}\right)$, for every real numbers $x$. Then,
ManipalManipal 2016
Solution:
$h(x)=\min \left(x, x^{2}\right)=\begin{cases}x, & x<0 \\ x^{2}, & 0 \leq x<1 \\ x, & x \geq 1\end{cases}$
It is evident from the above graph that the given function is continuous for all $x$.
since, there are sharp edges at $x=0$ and $x=1$,
the function is not differentiable at these points.
Also, at $x \geq 1$, the function represents a straight line having slope $1$ ,
therefore $h'(x)=1, \forall x \geq 1$