Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Let g(x) = x f(x), where $ f(x) = \begin{cases} x \sin \frac{1}{x} , & x \neq 0 \\ 0 , & x = 0 \end{cases}$. At x = 0

JEE MainJEE Main 1994Continuity and Differentiability

Solution:

Correct answer is (a) g is differentiable but g' is not continuousCorrect answer is (b) g is differentiable while f is not