Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Let
$f\left(x\right) = \frac{sin\,\pi x}{x^{2}},\quad x > 0.$
Let $x_{1}< x_{2} < 3 <\cdots < x_{n} < \cdots$ be all the points of local maximum of f
and $y_{1} < y_{2} < y_{3}^{ }< \cdots < yn < \cdots$ be all the points of local minimum of f.
Then which of the following options is/are correct?

JEE AdvancedJEE Advanced 2019Application of Derivatives

Solution:

$f \left(x\right)=\frac{sin\,\pi x}{x^{2}}$
$f '\left(x\right)=\frac{2x\,cos\,\pi x\left(\frac{\pi x}{2}-tan\,\pi x\right)}{x^{4}}$
$\Rightarrow \left|x_{n}-y_{n}\right| > 1$ for every $n$
$x_{1} > y_{1}$
$x_{n}\,\in\,\left(2n, 2n + 12\right)$
$x_{n+1} -x_{n} > 2.$

Solution Image