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Q. Let $f(x)=e^{\left|x^2-4 x+3\right|}$ then

Application of Derivatives

Solution:

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$ f(x)=e^{g(x)}$
$f ^{\prime}( x )= e ^{ g ( x )} \cdot g ^{\prime}( x )$
$\therefore$ Check the nature of $g(x)$.
$g ( x )$ is increasing $(\uparrow)$ in $(1,2) \cup(3, \infty)$
and decreasing $(\downarrow)$ in $(-\infty, 1) \cup(2,3)$.
$g ( x )$ is continuous $\forall x \in R$.
But non-derivable at $x=1,3$
$g(x)$ has local maximum at $x=2$,
and local minimum at $x=1,3$.