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Q. Let $f: R \rightarrow R$ be a function such that $f(x)=\frac{x^2+2 x+1}{x^2+1}$. Then

JEE MainJEE Main 2023Relations and Functions - Part 2

Solution:

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$ f(x)=\frac{(x+1)^2}{x^2+1}=1+\frac{2 x}{x^2+1} $
$ f(x)=1+\frac{2}{x+\frac{1}{x}}$