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Q. Let $f$ be the function defined by
$f(x)=\begin{cases} \frac{x^{2}-1}{x^{2}-2|x-1|-1}, & x \neq 1 \\ \frac{1}{2}, & x=1 \end{cases}$

BITSATBITSAT 2020

Solution:

For $x < 1, f(x)=\frac{x^{2}-1}{x^{2}+2 x-3}=\frac{x+1}{x+3}$
$\therefore \displaystyle\lim _{x \rightarrow 1^{-}} f(x)=\frac{1}{2}$
For $x > 1, f(x)=\frac{x^{2}-1}{x^{2}-2 x+1}=\frac{x+1}{x-1}$
$\therefore \displaystyle\lim _{x \rightarrow 1^{-}} f(x)=\infty$
$\therefore $ The function is not continuous at $x=1$