By applying LMVT, there exist at least one c$\in$(1,3) such that $\frac{f\left(3\right)-f\left(1\right)}{3-1} = f'\left(c\right)$
$\Rightarrow f\left(3\right)-f\left(1\right) = 2.\left|f\left(c\right)\right|^{2}+8 \Rightarrow f\left(3\right)-f\left(1\right) \ge 8$