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Q. Let f : [1,3] $\to$ R be a continuous function that is differentiable in (1, 3) an $f'(x)=|f(x)|2+4$ for all x $\in$ (1,3). Then,

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Solution:

By applying LMVT, there exist at least one c$\in$(1,3) such that $\frac{f\left(3\right)-f\left(1\right)}{3-1} = f'\left(c\right)$
$\Rightarrow f\left(3\right)-f\left(1\right) = 2.\left|f\left(c\right)\right|^{2}+8 \Rightarrow f\left(3\right)-f\left(1\right) \ge 8$