Question

Let $E=x y z$ and $A=\left\{(x, y, z) \in R^3: x^2+y^2+z^2=1\right.$ and $\left.x+y+z=1\right\}$ then over the set $A$

• A. global maximum value of $E$ is 0 .
• B. global minimum value of $E$ is $\frac{-4}{27}$.
• C. global maximum value of $x$ is 1 .
• D. global minimum value of $z$ is $\frac{-1}{3}$.

Answer 1

Answer: (A), (B), (C), (D)

Correct answer is (a) global maximum value of $E$ is 0 .Correct answer is (b) global minimum value of $E$ is $\frac{-4}{27}$.Correct answer is (c) global maximum value of $x$ is 1 .Correct answer is (d) global minimum value of $z$ is $\frac{-1}{3}$.