Question

Let $\Delta, \nabla \in\{\Lambda, V\}$ be such that $( p \rightarrow q ) \Delta( p \nabla q )$ is a tautology. Then

• A. $\Delta=\wedge, \nabla=\wedge$
• B. $\Delta=\vee, \nabla=\vee$
• C. $\Delta=\vee, \nabla=\wedge$
• D. $\Delta=\wedge, \nabla=\vee$

Answer 1

Answer: (B)

Given $( p \rightarrow q ) \Delta( p \nabla q )$
Option I $ \Delta=\wedge, \nabla=\vee$



Hence, it is tautology.
Option $4 \Delta=\wedge, \nabla=\wedge$