Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Let a tangent to the curve $y^2=24 x$ meet the curve $x y=2$ at the points $A$ and $B$. Then the mid points of such line segments $A B$ lie on a parabola with the

JEE MainJEE Main 2023Conic Sections

Solution:

$ y ^2=24 x$
$ a =6$
$ xy =2 $
$ AB \equiv ty = x +6 t ^2$.......(1)
$ AB \equiv T = S _1 $
$ kx + hy =2 hk $.........(2)
From (1) and (2)
$\frac{ k }{1}=\frac{ h }{- t }=\frac{2 hk }{-6 t ^2}$
$\Rightarrow$ then locus is $y ^2=-3 x$
Therefore directrix is $4 x=3$