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Q. Let a sample space be $S = \left\{\omega_{1}, \omega_{2}, ..., \omega_{6}\right\} $. Which of the following assignments of probabilities to each outcome is/are valid?
Outcomes
$\omega_{1}$ $\omega_{2}$ $\omega_{3}$ $\omega_{4}$ $\omega_{5}$ $\omega_{6}$
(i)$\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$
(ii)$\,\,\,\,$ $1\,\,\,\,$ $0\,\,\,\,$ $0\,\,\,\,$ $0\,\,\,\,$ $0\,\,\,\,$ $0\,\,\,\,$
(iii)$\,\,\,\,$ $\frac{1 }{ 8}\,\,\,\,$ $\frac{2 }{ 3}\,\,\,\,$ $\frac{1 }{ 3}\,\,\,\,$ $\frac{1 }{ 3}\,\,$ $-\frac{1 }{ 4}\,\,$ $-\frac{1 }{ 3}\,\,$
(iv)$\,\,\,\,$ $\frac{1 }{12}\,\,\,\,$ $\frac{1 }{12}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{1 }{ 6}\,\,\,\,$ $\frac{3 }{ 2}\,\,\,\,$
(v)$\,\,\,\,$ $0.1\,\,\,\,$ $0.2\,\,\,\,$ $0.3\,\,\,\,$ $0.4\,\,\,\,$ $0.5\,\,\,\,$ $0.6\,\,\,\,$

Probability

Solution:

(i) Condition I Each of the number $P\left(\omega_{i}\right)$ is positive and less than one.
Condition II : Sum of probabilities
$= \frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}=1$
Therefore, the assignment is valid.
(ii) Condition I : Each of the number $P\left(\omega_{i}\right)$ is either $0$ or $1$.
Condition II : Sum of the probabilities $= 1 + 0 + 0 + 0 + 0 + 0 = 1$
Therefore, the assignment is valid.
(iii) Condition I : Two of the probabilities $P\left(\omega_{3}\right)$ and $P\left(\omega_{6}\right)$ are negative, the assignment is nor valid.
(iv ) Since, $P\left(\omega_{6}\right)$ $= \frac{3}{2} > 1$, the assignment is not valid.
(v) Since, sum of probabilities
$= 0.1 + 0 .2 + 0.3 + 0.4 + 0 .5 + 0.6 = 2.1$.
the assignment is not valid.