1. Tardigrade
  2. Question
  3. Mathematics
  4. Let A be the vertex of parabola y = x 2-2 and B , C are the intersection points of the parabola with the circle x2+y2=8. Then the area of triangle A B C is

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Q. Let $A$ be the vertex of parabola $y = x ^2-2$ and $B , C$ are the intersection points of the parabola with the circle $x^2+y^2=8$. Then the area of triangle $A B C$ is

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Solution:

Solve P & S
$B \equiv(2,2)$
$\therefore (-2,2)$
$\therefore A=\frac{1}{2} \times 4 \times 4=8$

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