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Q. Let $A, B, C$ be three events in a probability space. Suppose that $P(A)=0.5, P(B)=0.3, P(C)=0.2$, $P(A \cap B)=0.15, P(A \cap C)=0.1$ and $P(B \cap C)=0.06$, the greatest possible value of $P\left(A^C \cap B^C \cap C^{C}\right)$ is [Note : $A^c$ denotes compliment of event $A$ ]

Probability

Solution:

Correct answer is (a) 0.31