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Q. Let $a, b, c$ be positive real numbers, such that $b x^{2}+$ $\left(\sqrt{(a+c)^{2}+4 b^{2}}\right) x+(a+c) \geq 0, \forall x \in R$, then $a, b, c$ are in:

Complex Numbers and Quadratic Equations

Solution:

$(a+c)^{2}+4 b^{2}-4 b(a+c) \leq 0$
$\Rightarrow (a-2 b+c)^{2} \leq 0$
$\Rightarrow a-2 b+c=0$
$\Rightarrow 2 b=a+c$
$\Rightarrow a, b, c$ are in A.P.