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  4. Let A and B be finite sets such that n(A-B)=18, n(A ∩ B) =25 and n(A ∪ B)=70 Then n(B) is equal to

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Q. Let $A$ and $B$ be finite sets such that $n(A-B)=18, n(A \cap B)$ $=25$ and $n(A \cup B)=70$ Then $n(B)$ is equal to

KEAMKEAM 2020

Solution:

$18+25+x=70$
$x=70-43$
$x=27$
$n(B)=27+25$
$=52$