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Q. Let $A=\{0,1,2,3,4,5,6,7\}$. Then the number of bijective functions $f: A \rightarrow A$ such that $f(1)+f(2)=3-f(3)$ is equal to

JEE MainJEE Main 2021Relations and Functions - Part 2

Solution:

$f(1)+f(2)=3-f(3)$
$\Rightarrow f(1)+f(2)=3+f(3)=3$
The only possibility is: $0+1+2=3$
$\Rightarrow$ Elements $1,2,3$ in the domain can be mapped with $0,1,2$ only.
So number of bijective functions.
$=3 ! \times 5 !=720$