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Q. Let $\left\{\frac{6^p-1}{5}\right\} x^2+(p-5)\left(p^2-4 p+3\right) x+\left[\frac{p-2}{3}\right]=0$ where $\{y\}$ and $[y]$ denote fractional part function and greatest integer function of y respectively. On throwing a normal dice, its outcome is considered as the value of $p$. Identify which of the following statement(s) is(are) correct?

Probability - Part 2

Solution:

$\left\{\frac{6^{ p }-1}{5}\right\}=0 \Rightarrow p=1,2,3,4,5,6$
$( p -5)\left( p ^2-4 p +3\right)=0 \Rightarrow p=1,3,5$
${\left[\frac{ p -2}{3}\right]=0 \Rightarrow 2 \leq p<5 \Rightarrow p=2,3,4 .}$