1. Tardigrade
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  4. Let (5+2 √6)n=p+f where n ∈ N and p ∈ N and 0<f<1 then the value of, (f2-f+p f-p) is

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Q. Let $(5+2 \sqrt{6})^n=p+f$ where $n \in N$ and $p \in N$ and $0
Binomial Theorem

Solution:

$\sin / S f^2-f+p f-p=-f(1-f)-p(1-f)=-[(p+f)(1-f)]$
where $p + f =(5+2 \sqrt{6})^{ n }$ and $1- f = f ^{\prime}=(5-2 \sqrt{6})^{ n }$ hence $f ^2- f + pf - p =-1$.