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Q. Lead is the final product formed by a series of changes in which the rate determining stage is the radioactive decay of uranium $ -238 $ with a half-life of $ 4.5\times {{10}^{9}}yr $ . What would be the age of a rock sample originally lead free in which the molar proportion of uranium to lead is now 1 : 3?

KEAMKEAM 2009

Solution:

All radioactive processes follow first order kinetics. Initially sample is free from lead. If its proportion is $ x, $ the amount of sample at time T is $ 4x $
$ \Rightarrow $ $ \frac{0.693}{4.5\times {{10}^{9}}yr}=\frac{2.303}{T}\log \frac{4x}{x} $
$ T=2\times 4.5\times {{10}^{9}}yr=9.0\times {{10}^{9}}yr $