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Q. $ \lambda_e, \, \lambda_p $ and $ \lambda_\alpha $ are the de-Broglie wavelength of electron, proton and $\alpha$ -particle. If all are accelerated by same potential, then

KEAMKEAM 2009Dual Nature of Radiation and Matter

Solution:

$ \lambda_e = \frac{ 12.27 }{ \sqrt V} \mathring{A} $
$ \lambda_p = \frac{ 0.201 }{ \sqrt V} \mathring{A} $
$ \lambda_\alpha = \frac{ 0.101 }{ \sqrt V} \mathring{A} $