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Q. L is angular momentum of an electron which is revolving around the nucleus of H-atom in first orbit of radius r. The angular momentum of same electron when it is revolving in bigger, orbit of radius 9 r is

Solution:

$L = \frac{nh}{2 \pi} \propto \, n ; $ but $r \, \propto \, n^2$
$\therefore $ $L \propto \sqrt{r}$