Question

$KMnO_{4}$ oxidises thiosulphate to $SO^{2-}_{4}$ as per reaction
$xMnO_{4}^{-} + 3S_{2}O^{2-}_{3} + H_{2}O \to xMnO_{2} + 6SO_{4}^{2-} + 2OH^{-}$
Find the value of $x$ in above reaction

Answer 1

$S_{2}O_{3}^{2-} + 10OH^{-} \to 2SO_{4}^{2-}+ 5H_{2}O + 8e^{-}] \times 3$
$\frac{MnO_{4}^{-} + 2H_{2}O + 3e^{-} \to MnO_{2} + 4OH^{-}] \times 8}{8MnO_{4}^{-} + 3S_{2}O_{3}^{2-} + H_{2}O \to 8MnO_{2} + 6SO_{4}^{2-} + 2OH^{-}}$