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Q. $ KMnO_4 $ gets reduced to

AMUAMU 2011The d-and f-Block Elements

Solution:

$KMnO_4$ is a powerful oxidising agent and gets reduced to
$(i)\, MnO_2$ in neutral medium.
$2KMnO_4 + H_2O \rightarrow 2KOH + 2MnO_2 + 3[O]$
$(ii)\, K_2MnO_4$ in alkaline medium.
$2KMnO4 + 2KOH \rightarrow 2K_2MnO_4$
$+ H_2O + [O]$
$(iii) \,Mn^{2+} $ in acidic medium.
$MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$