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  4. textKMn textO text4 oxidises oxalic acid in acid medium. The number of textC textO2 molecules produced as per the balanced equation is :

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Q. $ \text{KMn}{{\text{O}}_{\text{4}}} $ oxidises oxalic acid in acid medium. The number of $ \text{C}{{\text{O}}_{2}} $ molecules produced as per the balanced equation is :

EAMCETEAMCET 1998

Solution:

The balanced chemical equation of the oxidation of oxalic acid is as under: $ 2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}+5\underset{COOH}{\mathop{\underset{|}{\mathop{COOH}}\,}}\,\xrightarrow{{}} $ $ {{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+10C{{O}_{2}}+8{{H}_{2}}O $ From the above equation it is clear that in . balanced chemical equation of oxidation o oxalic acid by KMn04 in acidic medium evolve 10 molecules of $ C{{O}_{2}}. $