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Q.
Kirchhoff's I and II laws are based on conservation of:
AFMCAFMC 2003
Solution:
From Kirchhoff's first law, in an electric circuit, the algebraic sum of the currents meeting at any junction in the circuit is zero, that is
$i_{1}+i_{2}+i_{3}+i_{4}=0$
$\Rightarrow \sum i=0$
Thus, Kirchhoff's first law expresses the conservation of charge.
Kirchhoff's second law states that in any closed mesh of a circuit, the algebraic sum of the products of current and the resistance in each . part is equal to the algebraic sum of the emfs in that mesh
i.e., $\Sigma i R=\Sigma E$
Hence, second law expresses the conservation of energy.
